August 13, 2026 · Reference · LibreTimesIntegrals with RadicalsSergeyMathematical AnalysisIndefinite integrals of expressions containing radicals. ∫x−a dx=32(x−a)3/2+C ∫x±a1 dx=2x±a+C ∫a−x1 dx=−2a−x+C ∫xx−a dx=⎩⎨⎧32a(x−a)3/2+52(x−a)5/2, or32x(x−a)3/2−154(x−a)5/2, or152(2a+3x)(x−a)3/2+C ∫ax+b dx=(3a2b+32x)ax+b+C ∫(ax+b)3/2 dx=5a2(ax+b)5/2+C ∫x±ax dx=32(x∓2a)x±a+C ∫a−xx dx=−x(a−x)−aarctanx−ax(a−x)+C ∫a+xx dx=x(a+x)−aln[x+x+a]+C ∫xax+b dx=15a22(−2b2+abx+3a2x2)ax+b+C ∫x(ax+b) dx=4a3/21[(2ax+b)ax(ax+b)−b2lnax+a(ax+b)]+C ∫x3(ax+b) dx=[12ab−8a2xb2+3x]x3(ax+b)+8a5/2b3lnax+a(ax+b)+C ∫x2±a2 dx=21xx2±a2±21a2lnx+x2±a2+C ∫a2−x2 dx=21xa2−x2+21a2arctana2−x2x+C ∫xx2±a2 dx=31(x2±a2)3/2+C ∫x2±a21 dx=lnx+x2±a2+C ∫a2−x21 dx=arcsinax+C ∫x2±a2x dx=x2±a2+C ∫a2−x2x dx=−a2−x2+C ∫x2±a2x2 dx=21xx2±a2∓21a2lnx+x2±a2+C ∫ax2+bx+c dx=4ab+2axax2+bx+c+8a3/24ac−b2ln2ax+b+2a(ax2+bx+c)+C ∫xax2+bx+c dx=48a5/21(2aax2+bx+c(−3b2+2abx+8a(c+ax2))+3(b3−4abc)lnb+2ax+2aax2+bx+c)+C ∫ax2+bx+c1 dx=a1ln2ax+b+2a(ax2+bx+c)+C ∫ax2+bx+cx dx=a1ax2+bx+c−2a3/2bln2ax+b+2a(ax2+bx+c)+C ∫(a2+x2)3/2dx=a2a2+x2x+C
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