August 13, 2026 · Reference · LibreTimesIntegrals of Rational FunctionsSergeyMathematical AnalysisIndefinite integrals of rational expressions. ∫(x+a)21dx=−x+a1+C ∫(x+a)ndx=n+1(x+a)n+1+C,n=−1 ∫x(x+a)ndx=(n+1)(n+2)(x+a)n+1((n+1)x−a)+C ∫1+x21dx=arctanx+C ∫a2+x21dx=a1arctanax+C ∫a2+x2xdx=21ln∣a2+x2∣+C ∫a2+x2x2dx=x−aarctanax+C ∫a2+x2x3dx=21x2−21a2ln∣a2+x2∣+C ∫ax2+bx+c1dx=4ac−b22arctan4ac−b22ax+b+C ∫(x+a)(x+b)1dx=b−a1lnb+xa+x, a=b+C ∫(x+a)2xdx=a+xa+ln∣a+x∣+C ∫ax2+bx+cxdx=2a1ln∣ax2+bx+c∣−a4ac−b2barctan4ac−b22ax+b+C
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