August 13, 2026 · Reference · LibreTimesIntegrals with ExponentialsSergeyMathematical AnalysisIndefinite integrals of expressions containing exponentials. ∫eax dx=a1eax+C ∫xeax dx=a1xeax+2a3/2iπerf(iax),+C where erf(x)=π2∫0xe−t2dt ∫xex dx=(x−1)ex+C ∫xeax dx=(ax−a21)eax+C ∫x2ex dx=(x2−2x+2)ex+C ∫x2eax dx=(ax2−a22x+a32)eax+C ∫x3ex dx=(x3−3x2+6x−6)ex+C ∫xneax dx=axneax−an∫xn−1eaxdx ∫xneax dx=an+1(−1)nΓ[1+n,−ax],+C whereΓ(a,x)=∫x∞ta−1e−tdt ∫eax2 dx=−2aiπerf(ixa)+C ∫e−ax2 dx=2aπerf(xa)+C ∫xe−ax2 dx=−2a1e−ax2+C ∫x2e−ax2 dx=41a3πerf(xa)−2axe−ax2+C
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